#3a. The International Space Station iss (assume that the weight of the lss, ifi
ID: 3160994 • Letter: #
Question
#3a. The International Space Station iss (assume that the weight of the lss, ifit were on the surface ofthe approximately 990,000 pounds) orbits the earth at an altitude of approximately 250 miles above the surface of the earth. If the orbit to be changed to 350 miles above the earth's surface and assuming a circular orbit, what is the attractive force that the earth would have to exert on it to keep it in orbit? Give your answer in the form 'a.bc x 10Nyo" N. Note that the unit representation should not be included in your answer input since it is not inside the symbols! Hint's: The weight of the Iss is given in pounds and the distance in miles. These are from the British system of measurements. Hence, you need to convert them into the sl system before beginning to work the problem. You also need to obtain the mass of the earth. You will find this in the inside cover of the physics textbook, or, you can do an internet search using Google or another search engine. Answer: Answer: m3b. What would be the magnitude of the earth's gravitational field at the new location of the lss? Give your answer in the form "a bo x 10A(y)" N/kg.Explanation / Answer
Electric force at the old location is
F=G*Mearth*m/r^2
Mearth=mass of earth=5.972*10^24 kg
m is mass of satellite=990000 pound=449056.446 kg
250 mile=402.336 km
r=6371+402.336=6773.336 km=6773336 m
so F=3898893.102 N
F=3.90*10^6
(b) for new orbit
r=563.27+6371=6934.27 km=6934270 m
rest all is same so
F=3720018.265 N
F=3.72*10^6 N
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