14. Charge is given in microcoulombs. What must you multiply the charge by to us

Question

14. Charge is given in microcoulombs. What must you multiply the charge by to use Coulomb's law to calculate the electric force?

10^3

10^6

10^-6

10^-3

4.3 × 104 N/C

8.5 × 10-7 N/C

8.5 × 102 N/C

8.1 × 10-5 N/C

2.8 × 1016 N/C

1.4 × 1015 N/C

7.0 × 1016 N/C

2.8 × 1015 N/C

4.3 × 104 N/C

8.5 × 10-7 N/C

8.5 × 102 N/C

8.1 × 10-5 N/C

16. Object A has charge and is positioned from object B, which has charge . What is the magnitude of the electric field at the center of object A? Let the constant k =

2.8 × 1016 N/C

1.4 × 1015 N/C

7.0 × 1016 N/C

2.8 × 1015 N/C

9.0 x 109 N m 2/C2

Explanation / Answer

14) 1 microcolumb = 10^-6 C

third option is correct.

15) E = kq/r^2 = 9e9*1.9e-9/0.02^2 = 4.3*10^4 N/C

first option

16)E = 9e9*0.20/(0.8e-3)^2

= 2.8 × 10^15 N/C

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