Question
The car starts moving to the right and its speed to the right simply continues to increase.
(B) Determine how the velocity varies for velocity initially to the right and with constant acceleration to the left.
In this case the velocity is initially positive but its value decreases by 1.3 m/s for each second that passes. Because the acceleration is to the left, it is negative. The velocity vs. time graph satisfies the equation v(t) = vi + at = (____m/s2) + (_____m/s2)t?
The graphs in the Active figure show the velocity vs. time and position vs. time for various choices of the acceleration. The car moving along a straight road is a problem in one-dimensional motion, and the question calls for using the relation between position and time to calculate speed and velocity. Determine how the velocity varies for positive acceleration and initial velocity to the right. The acceleration vs. time plot for constant acceleration is a straight line parallel to the time axis. It lays above the origin for acceleration to the right. During the acceleration, the velocity increases by 1.3 m/s each second, so the velocity vs. time graph is a line with a slope of 1.3 m/s per second, and v(t) = v_i + at = 1.3 m/s + 1.3 m/s^2 The car starts moving to the right and its speed to the right simply continues to increase. Determine how the velocity varies for velocity initially to the right and with constant acceleration to the left. In this case the velocity is initially positive but its value decreases by 1.3 m/s for each second that passes. Because the acceleration is to the left, it is negative. The velocity vs. time graph satisfies the equation v(t) = v_i + at = 1.3 m/s + 1.3 m/s^2 The car moves initially to the right and while it moves its velocity keeps decreasing. Eventually, its velocity passes through zero and thereafter the car is backing up with increasing speed. Check whether this description of motion is consistent with the graphs shown in the Active Figure and the motion it illustrates. Deceleration is an acceleration that causes an object to slow down. Would it be consistent with our sign conventions to define deceleration instead as "negative acceleration?" Yes No
Explanation / Answer
The 1st answer will be 0 and +1.3 as it started from rest and acceleration is positive.
For the 2nd part, the acceleration is negative. So the 2nd blank will be (-1.3) but for the 1st blank more information is needed. Initial velocity can be found either in the figure or can be calculated from the time it was acclerating for, in the 1st part.
