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Suppose that 50% of the subscribers of a cable television company watch the shop

ID: 3160574 • Letter: S

Question

Suppose that 50% of the subscribers of a cable television company watch the shopping channel at least once a week. The cable company is trying to decide whether to replace this channel with a new local station. A survey of 100 subscribers will be undertaken. The cable company has decided to keep shopping channel if the sample proportion is greater than 0.57. What is the approximate probability that the cable company will keep the shopping channel even though the true proportion is only 0.50? Suppose that 50% of the subscribers of a cable television company watch the shopping channel at least once a week. The cable company is trying to decide whether to replace this channel with a new local station. A survey of 100 subscribers will be undertaken. The cable company has decided to keep shopping channel if the sample proportion is greater than 0.57. What is the approximate probability that the cable company will keep the shopping channel even though the true proportion is only 0.50?

Explanation / Answer

We first get the z score for the critical value. As z = (x - u) / s, then as          
          
x = critical value =    0.57      
u = mean = p =    0.5      
          
s = standard deviation = sqrt(p(1-p)/n) =    0.05      
          
Thus,          
          
z = (x - u) / s =    1.4      
          
Thus, using a table/technology, the right tailed area of this is          
          
P(z >   1.4   ) =    0.080756659 [ANSWER]

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