The average expenditure on Valentine\'s Day was expected to be $100.89 (USA Toda
ID: 3159183 • Letter: T
Question
The average expenditure on Valentine's Day was expected to be $100.89 (USA Today, February 13, 2006). Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 40 male consumers was $135.67, and the average expenditure in a sample survey of 32 female consumers was $68.64. Based on past surveys, the standard deviation for male consumers is assumed to be $35, and the standard deviation for female consumers is assumed to be $16.
A) What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females (to 2 decimals)?
B) At 99% confidence, what is the margin of error (to 2 decimals)?
C) Develop a 99% confidence interval for the difference between the two population means (to 2 decimals).
Explanation / Answer
a)
Calculating the means of each group,
X1 = 135.67
X2 = 68.64
hence,
X1 - X2 = 67.03 [ANSWER]
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b)
Calculating the standard deviations of each group,
s1 = 35
s2 = 16
Thus, the standard error of their difference is, by using sD = sqrt(s1^2/n1 + s2^2/n2):
n1 = sample size of group 1 = 40
n2 = sample size of group 2 = 32
Thus, df = n1 + n2 - 2 = 70
Also, sD = 6.214901447
For the 0.99 confidence level, then
alpha/2 = (1 - confidence level)/2 = 0.005
t(alpha/2) = 2.647904624
Hence,
Margin of error = t(alpha/2) * sD = 16.45646628 [ANSWER]
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c)
Thus,
lower bound = [X1 - X2] - t(alpha/2) * sD = 50.57353372
upper bound = [X1 - X2] + t(alpha/2) * sD = 83.48646628
Thus, the confidence interval is
( 50.57353372 , 83.48646628 ) [ANSWER]
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Hi! If you use another method/formula in calculating the degrees of freedom in this t-test, please resubmit this question together with the formula/method you use in determining the degrees of freedom. That way we can continue helping you! Thanks!
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