The atomic weight of carbon is 12, and some scientists wish to compare two diffe

Question

The atomic weight of carbon is 12, and some scientists wish to compare two different ways of measuring it. They want to test whether or not the means of the two methods are different at = .10. Perform a hypothesis test to determine whether or not the means of the two methods are significantly different. First, determine whether or not you should assume the variances are equal by performing the Folded F test. The summary of the results is given

Method 1: n1 = 10 X(bar) 1 = 12.2006 S1 = 0.00792

Method 2: n2 = 5 X(bar) 2 = 12.0143 S2 = 0.0132

Explanation / Answer

F = ( 0.00792 / 0.0132) ^2 = 0.36

for alpha = 0.05 df = 10-1 = 9 df2 = 5-1 = 4

critical value : 6.00

since F < critical value we assume variance sequal

t = ( 12.2006 - 12.0143 ) / ( srqt 0.00792^2 / 10 + 0.0132^2 / 5 )

t = 29.05

since t > critical value ( 1.771 )

we reject Ho

the means are different

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.