You draw marbles from a jar without replacement. What is the probability of even

ID: 3155853 • Letter: Y

Question

You draw marbles from a jar without replacement. What is the probability of events A and B occurring?

A jar has 6 red marbles out of a total of 20 marbles the same size. A: getting a red marble in the first drawing from the jar. B: getting a marble that is not red in the second drawing from the jar.

Correct Answer: 22.1 <----- How?

Explanation / Answer

You draw marbles from a jar without replacement. What is the probability of events A and B occurring?

A jar has 6 red marbles out of a total of 20 marbles the same size.

A: getting a red marble in the first drawing from the jar.

B: getting a marble that is not red in the second drawing from the jar.

There are 6 red out of 20 marbles.

Hence,

P(A) = 6/20

Note that by Bayes' Rule,

P(A n B) = P(A) P(B|A)

If a red marble is drawn first, then 14 nonred remain out of 19. Hence, P(B|A) = 14/19, so

= (6/20)*(14/19)

= 0.221052632 [ANSWER]

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You draw marbles from a jar without replacement. What is the probability of even

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