if a population Has a standard deviation of 18 what is the minimum number of sam

Question

if a population Has a standard deviation of 18 what is the minimum number of samples that need to be averaged in order to be 95% confident that the average of the mean is within 5 of the true mean if a population Has a standard deviation of 18 what is the minimum number of samples that need to be averaged in order to be 95% confident that the average of the mean is within 5 of the true mean if a population Has a standard deviation of 18 what is the minimum number of samples that need to be averaged in order to be 95% confident that the average of the mean is within 5 of the true mean

Explanation / Answer

standard deviation = 18

margin of error = 5

the formula for margin of error = zscore*standard deviation/sqrt(n)

z score for 95% = 1.96

according to the formula

5 = 1.96*18/sqrt(n)

squaring both sides

n = (1.96*18/5)^2

n = 49.78 = 50

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