if 2.34g of the vapor of a volatile liquid is able to fill a 567-ml flask at 26C

Question

if 2.34g of the vapor of a volatile liquid is able to fill a 567-ml flask at 26C and 687mm Hg, what is the molecular weight of the liquid? *write answer in decimal for to one decimal place* if 2.34g of the vapor of a volatile liquid is able to fill a 567-ml flask at 26C and 687mm Hg, what is the molecular weight of the liquid? *write answer in decimal for to one decimal place* if 2.34g of the vapor of a volatile liquid is able to fill a 567-ml flask at 26C and 687mm Hg, what is the molecular weight of the liquid? *write answer in decimal for to one decimal place*

Explanation / Answer

Answer – We are given, mass of vapor of a volatile liquid = 2.34 g , volume = 567 mL , P = 687 mmHg , T = 26+273 = 299 K

First we need to calculate the density of the vapor of a volatile liquid in g/L

So, volume need to convert the mL to L

1 mL = 0.001 L

So, 567 mL = ?

= 0.687 L

Density = mass / volume

             = 2.34 g / 0.567           

             = 4.13 g/L

Now we need to convert the P mmHg to atm

760 mmHg = 1 atm

So, 687 mmHg = ?

= 0.904 atm

Now we know the formula

Density = PM/RT

So, M = molar Mass

M = density *RT / P

     = 4.13 g/L *0.0821 L.atm.mol-1.K-1*299 K / 0.904 atm

      = 112.1 g/mol

So, the molecular weight of the liquid is 112.1 g/mol.

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