A box contains 6 blue marbles,2 red marbles and 4 black marbles. If 3 marbles ar
ID: 3153253 • Letter: A
Question
A box contains 6 blue marbles,2 red marbles and 4 black marbles. If 3 marbles are randomly selected from the box without replacement what is the probability of gettingA) two red and one blue given that the last one is red
B) one of each color if the second trail is black A box contains 6 blue marbles,2 red marbles and 4 black marbles. If 3 marbles are randomly selected from the box without replacement what is the probability of getting
A) two red and one blue given that the last one is red
B) one of each color if the second trail is black
A) two red and one blue given that the last one is red
B) one of each color if the second trail is black
Explanation / Answer
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Given that box contains
6 blue marbles,2 red marbles and 4 black marbles.
a) Probability of getting 3 marbles if 3 rd marble is red when two red and one blue are to be drawn
p(BRR)+p(RBR)
=(6/12)*(2/11)*(1/10) + (2/12)*(6/11)*(1/10)
=24/1320
=0.01818
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b) Probability that each different color is drawn is second is black
p(Blue,Black,red)+p(red, black, blue)
=6/12* 4/11* 2/10+2/12 * 4/11* 6/10
=4/55
=0.0727
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