A telemarketing firm has studied the effects of two factors on the response to i
ID: 3152361 • Letter: A
Question
A telemarketing firm has studied the effects of two factors on the response to its television advertisements. The first factor is the time of day at which the ad is run, while the second is the position of the ad within the hour. The data in following table, which were obtained by using a completely randomized experimental design, give the number of calls placed to an 800 number following a sample broadcast of the advertisement. If we use Excel to analyze these data, we obtain the output in table below.
Perform graphical analysis to check for interaction between time of day and position of advertisement. Then test for interaction with = .05.
Make pairwise comparisons of the morning, afternoon, and evening times by using Tukey simultaneous 95 percent confidence intervals. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)
Make pairwise comparisons of the four ad positions by using Tukey simultaneous 95 percent confidence intervals. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)
Which time of day and advertisement position maximizes consumer response? Compute a 95 percent (individual) confidence interval for the mean number of calls placed for this time of day/ad position combination. (Round your answers to 2 decimal places.)
A telemarketing firm has studied the effects of two factors on the response to its television advertisements. The first factor is the time of day at which the ad is run, while the second is the position of the ad within the hour. The data in following table, which were obtained by using a completely randomized experimental design, give the number of calls placed to an 800 number following a sample broadcast of the advertisement. If we use Excel to analyze these data, we obtain the output in table below.
Explanation / Answer
If the P-value is greater than sigificance level, we do not reject the null hypothesis, otherwise we reject the null hypothesis .
(a)
F = .36, p-value = .8981, do not reject H0: there is no interaction
Graphical analysis supports the above conclusion.
(b)
F = 904.01, p-value = less than .05; reject H0: time of day is important
(c)
F = 100.96, p-value = less than .001; reject H0: position of the ads is important
(d)
Confidence interval = (difference in means) +- q*sqrt(MSE/n)
Case 1: M-A
Confidence interval = (47.50-65.67) +- 3.53*sqrt(12.417/12) = [-21.76,-14.58]
Case 2: M-E
Confidence interval = (47.50-107.17) +- 3.53*sqrt(12.417/12) = [-63.26,-56,08]
Case 3 : A-E
Confidence interval = (65.67-107.17) +- 3.53*sqrt(12.417/12) = [-45.09,-37.91]
Please ask the rest two parts seperately.
Tukey q.05 = 3.53, MSE = 12.417 uM – uA: [-21.76,-14.58] uM – uE: [-63.26,-56,08] uA – uE: [-45.09,-37.91]Related Questions
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