The U.S. Senate now has 41, 54, and 2 independents. A tobacco randomly selects 5

Question

The U.S. Senate now has 41, 54, and 2 independents. A tobacco randomly selects 5 to lobby. What is the probability of choosing 5 Republicans? Assuming the wants to influence that vote and Republicans are more likely to vote in favor of tobacco is random selection a good way to choose, in this situation? Explain. An bulb has probability of 98% of lasting for 750 hours. What is the probability a random bulbs will not last 750 hours? Suppose you buy 2 bulbs. What is the probability they will both full before 750 hours? What is the probability that your will have light for 750 hours, using both bulbs? Is a study on greater and to drunk driving, the following results were observed if a subject is randomly selected. What is the probability the subject the problem What is the probability the subject was female, assuming they thought the problem are not services? Recall that a Binomial probability distributions requires fixed number of trials independence of trials There are 12 face cards in a standard deck of 52 cards. You select 9 cards from the deck You are looking for force cards. Which of the situation below a) or b) allows you to use a Binomial Probability Distribution? Carefully explain your answer the definition above with replacement without replacement

Explanation / Answer

1a)

Probability of choosing 5 republicans = number of ways of choosing 5 republicans/total number of ways of choosing five senators

= 54C5/100C5 = (54!/(49!*5!))/ (100!/(95!*5!)) = 3162510/75287520 = 0.042

1b) No, because as we see from above calculation, it is very unlikely that randomly selected senators will all be republicans.

2a)

Bulb will either last for 750 hours or not.

P(random bulb will not last for 750) = 1 - P(bulb lasts for 750 hours)

= 1 - 0.98 = 0.02 = 2%

2b)

P(both bulbs fail before 750 hours) = P(a rondom bulb fails before 750)*P(a rondom bulb fails before 750)

= 0.02*0.02 = 0.0004 = 0.04 %

2c)

P(will have light for 750 hours using both) = P(at least one bulb lasts for 750 hours) = 1- P(both fail before 750 hours) = 1- 0.0004 = 0.9996 = 99.6%

3a) Numbers in table are not clearly readable, edit the calculation below if I have misread any number.

Total number of subjects = 419+332+357+306 = 1414

P(subject fel problem was serious or was male) = (332+357+306)/1414 = 0.7036

3b)

P(female assuming they felt problem was not serious) = P(subject was female felt problem is not serious)/P(subject felt problem was not serious) = 332/(332+306) = 0.5203

I am supposed answer maximum three questions in a post.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.