The function f: Z rightarrow Z, f(n) = n^2 is not an onto function. Which of the

Question

The function f: Z rightarrow Z, f(n) = n^2 is not an onto function. Which of the following sets is an appropriate co-domain that would make the function onto? 1.{1, 4, 9, 16, ....} 2.(0, 1, 4, 9, 16, ....} 3. N 4. None of these. Which of the following represents a well-defined function that is onto? 1 f: Z rightarrow N, f(n) = |n| 2. f: Z rightarrow Z, m = |n| 3.f: Z rightarrow (N Union {0}), f(n) = |n| 4 f: R rightarrow N, f(n) = |n| Consider the function, f: Z rightarrow Z, f(x) = 3x + 7 Which of the following is true for this function? The function is both one to one and onto. The function is neither one to one nor onto. The function is one to one, but it is not onto. The function is onto, but it is not one to one.

Explanation / Answer

Questio:11

Option (2) is correct: { 0, 1 ,4, 9 , 16 ... }

since each element in codomain has some element in domain

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