A home builder has six different house models for customers to select. He is sta

Question

A home builder has six different house models for customers to select. He is starting a new subdivision and will build four different sample models for potential customers to view along one street in the new subdivision. How many different arrangements of the four sample homes are possible?

360 arrangements

30 arrangements

24 arrangements

15 arrangements

An election has five items on the ballot. The first item of the ballot has 4 choices, the second item has 6 choices, the third item has 5 choices, the fourth item has 2 choices, and the fifth item has 2 choices.

Assuming no item ends in a tie, how many different configurations of winning choices are possible?

11,628 configurations

480 configurations

120 configurations

19 configurations

360 arrangements

30 arrangements

24 arrangements

15 arrangements

Explanation / Answer

1) Given that sample models = 4

out of 4 sample modles he can arrange differently in 4 factorial ways

therefore total number of different arrangements of four sample homes = 4! = (4*3*2*1) = 24 arrangements

ANSWER (C) (24)

2) The first item of the ballot has 4 choices, the second item has 6 choices, the third item has 5 choices, the fourth item has 2 choices, and the fifth item has 2 choices.

Therefore, different configurations of winning choices are possible are = 4*6*5*2*2 = 480

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