The distance s (in feet) covered by a motorcycle traveling in a straight line an

Question

The distance s (in feet) covered by a motorcycle traveling in a straight line and starting from rest in t sec is given by the function
s(t) = ?0.1t3 + 4t2 + 25t
Calculate the motorcycle's average velocity over the time interval [2, 2 + h] for h = 1, 0.1, 0.01, 0.001, 0.0001, and 0.00001. (Round your answers to four decimal places.)
h = 1

h = 0.1

h = 0.01

h = 0.001

h = 0.0001

h = 0.00001


Use your results to guess at the motorcycle's instantaneous velocity at t = 2. (Round your answer to one decimal place.)

Explanation / Answer

If we use 2 in the equation, we get s(2) = 0.1*8 +4*4 + 25*2 = 66.8 to find where the motorcylce is at the end of the time intervals, we use the final time. For example, after 0.1 seconds we get s(2.1) = 0.1*9.261 + 4*4.41 + 25*2.1 = 71.0661 To find average velocity, we divide change in distance (let's say it is in meters) by change it time [s(2.1) - s(2)]m/[2.1s - 2s] = 42.661 m/s substitutine in all of the times, we get 46.9000 for h = 1 42.6610 42.2460 42.2046 42.2005 42.2000 seems to be heading to the limit 42.2

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.