The distance between a lens and its upright image of an object is 4.50 cm; this

Question

The distance between a lens and its upright image of an object is 4.50 cm; this image falls to the left of the object, and the lens forming the image is to the right of both the object and the image. The magnification is +3.00.

a. Find the object distance p1.

b. Find the focal length of the lens f1.

c. A second lens of focal length f2=+30.0cm is no placed 20.0cm to the right of the first lens. Find the position of the final image q2 measured from the second lens.

Explanation / Answer

1/v+1/u= 1/f [ u is object distance and v is image distance] v/u= 3(given) =>v=3u =>u= 4.5/3=1.5 cm 1/4.5+1/1.5 = 1/f =>f=1.125 cm Image from the first lens will act as a object for the second lens =>u= 24.5 1/v + 1/24.5 =1/30 =>v=-133.63 cm i means final image is formed at 133 .63 cm to right of second lens

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