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Suppose that the probability for a student to get a free lift to a university on

ID: 3134299 • Letter: S

Question

Suppose that the probability for a student to get a free lift to a university on any morning is 0.4. The student needs to get a taxi if she/he does not get a lift and she/he needs to pay 20 QAR for a Taxi.. a. Determine the probability that in a week (five days), the student will get a lift only twice? b. Determine the probability that the student will get his/her first lift on the third day? c. Suppose a given month with 20 days. What is expectation of the amount of money that the student needs to pay in a month. (a) What is the mean number of days until eight computers fail in the same day?

Explanation / Answer

the probability for a student to get a free lift to a university on any morning=p=0.4

hence the probability of not getting a free lift to a university on any morning=1-0.4=0.6

a) let X denote the number of times a student get a lift in 5 days.

so X~Bin(5,0.4)

hence pmf of X is P[X=x]=5Cx0.4x(1-0.4)5-x

hence the probability that the student will get 2 lifts is

P[X=2]=5C20.420.63=0.3456 [answer]

b) the probability that the student will get his/her first lift on the third day

=probability that the student will not get a lift on the first day*probability that the student will not get a lift on the second day*probability that the student will get a lift on the third day

=0.6*0.6*0.4=0.144 [answer]

c) let Y denotes the amount the student need to pay on one day.

so if he/she gets a free lift he/she need not to pay anything. hence Y=0 with probability 0.4

if he/she does not get a free lift he/she needs to pay 20 QAR for a taxi. so Y=20   with probability 0.6

hence the expected amount of money that the student need to pay on one day is

E[Y]=0*0.4+20*0.6=12 QAR

hence in a month or 20 days the expected amount is 20*E[Y]=20*12=240 QAR [answer]

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