A study was conducted to compare the resting pulse rate among smokers and non-sm
ID: 3131729 • Letter: A
Question
A study was conducted to compare the resting pulse rate among smokers and non-smokers. The data are summarized in the table below. The pulse rate distribution in each group can be assumed to be normal, and equal population variances can be assumed in the two groups
Conduct the appropriate test to see if the mean resting pulse rate for smokers is higher than that for non-smokers. Show all work and include all steps (hypotheses, rejection region, p-value, decision and conclusion) for full credit.
Resting Pulse rate (bpm) Group Sample Size Mean SD Smokers 35 76.4 4 Non-Smokers 40 73.7 3.2Explanation / Answer
Let
u1 = mean resting pulse rate for smokers
u2 = mean resting pulse rate for nonsmokers
Formulating the null and alternative hypotheses,
Ho: u1 - u2 <= 0
Ha: u1 - u2 > 0 [HYPOTHESES]
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At level of significance = 0.05
As we can see, this is a right tailed test.
Calculating the means of each group,
X1 = 76.4
X2 = 73.7
Calculating the standard deviations of each group,
s1 = 4
s2 = 3.2
Thus, the pooled standard deviation is given by
S = sqrt[((n1 - 1)s1^2 + (n2 - 1)(s2^2))/(n1 + n2 - 2)]
As n1 = 35 , n2 = 40
Then
S = 3.594821237
Thus, the standard error of the difference is
Sd = S sqrt (1/n1 + 1/n2) = 0.832039439
As ud = the hypothesized difference between means = 0 , then
z = [X1 - X2 - ud]/Sd = 3.245038484
Getting the critical value using table/technology, as this is right tailed 0.05 level,
zcrit = 1.645
Hence, we reject Ho when z > 1.645. [ANSWER, REJECTION REGION]
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Getting the p value using table/ technology,
p = 0.000587174 [ANSWER, P VALUE]
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As z < 1.645, and P < 0.05, we REJECT THE NULL HYPOTHESIS. [DECISION]
Hence, there is significant evidence at 0.05 level that the mean resting pulse rate for smokers is higher than that for non-smokers. [CONCLUSION]
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