One of the games in the Oklahoma lottery is to pay $1 to select a 3-digit number

Question

One of the games in the Oklahoma lottery is to pay $1 to select a 3-digit number. Every Wednesday evening, the lottery commission randomly places a set of 10 balls numbered 0 - 9 in each of three containers. After a complete mixing of the balls, one ball is selected from each container. First, suppose you purchase a lottery ticket. What is the probability that your 3-digit number will be the winning number? Which of the three probability approaches (subjective, classical, or relative frequency) did you employ in obtaining your answer to the first part? Explain how you know.

Explanation / Answer

There are 10*10*10 = 1000 such numbers.

Hence, as you only purchase one ticket, then

P(win) = 1/1000 or 0.001 [ANSWER]

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I used CLASSICAL PROBABILITY, since I counted the number of successes over number of possibilities. [ANSWER: CLASSICAL]

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