One of the games in the Oklahoma lottery is to pay $1 to select a 3-digit number

Question

One of the games in the Oklahoma lottery is to pay $1 to select a 3-digit number. Every Wednesday evening, the lottery commission randomly places a set of 10 balls numbered 0 – 9 in each of three containers. After a complete mixing of the balls, one ball is selected from each container. First, suppose you purchase a lottery ticket. What is the probability that your 3-digit number will be the winning number? Which of the three probability approaches (subjective, classical, or relative frequency) did you employ in obtaining your answer to the first part? Explain how you know.

Explanation / Answer

AS IN THIS CASE THE THREE DIGIT NUMBER CAN BE LIKE 011

WHICH MEANS THE HUNDRED PLACE CAN BE OCCUPIED BY THE 0 BECAUSE EACH CONTAINER HAS 10 NUMBERS FROM 0 TP 9

ALSO THE NUMBERS CAN REPEAT LIKE 111,999

SO THE TOTAL 3 DIGIT NUMBER CAN BE FORMED = 10*10*10 = 1000

PROBABILITY OF I HAVE THE WINNING NUMBER = 1/1000 = 0.001

WE HAVE APPROACHED TO FIND THE PROBABILITY BY THE CLASSICA WAY OF PROBABILITY.

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