The demand (in number of copies per day) for a city newspaper x, has historicall

Question

The demand (in number of copies per day) for a city newspaper x, has historically been 47,000 66,000, 86,000, 101,000 or 111,000 with the respective probabilities.2,.35,.3, 1, and.05 Find the expected demand (Round your answer to the nearest whole number.) Using Chebyshev's Theorem find the minimum percentage of all possible daily demand values that will fall in the interval [mu_x plusminus 2 sigma_x]. (Round your answer to the nearest whole number. Input your answers to minimum percentage and percentage of all possible as percents without percent sign.) The minimum percentage of all possible daily demand values is percent. Calculate the interval (mu_x plusminus 2sigma_x]. According to the probability distribution of demand x previously given what percentage of all possible daily demand values (all in the interval (mu_x plusminus 2sigma_x]? (Round your intermediate values to the nearest whole number. Round your answers to the nearest whole number. Input your answers to minimum percentage and percentage of all possible as percents without percent sign.) The interval is The percentage of all possible daily demand values that fall in the interval is percent.

Explanation / Answer

x 47000 66000 86000 101000 111000 p 0.2 0.35 0.3 0.1 0.05 xp 9400 23100 25800 10100 5550 (x-mu)^2p 145260500.00 1524600000.00 2218800000.00 1020100000.00 616050000.00 Mean 73950 std dev 74329.06901 mu-2 sigma -74708.13802 mu+2sigma 222608.138 Perentage falling 100%

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