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This is very important to me. Please, if you are not sure, please do not try to

ID: 3126104 • Letter: T

Question

This is very important to me. Please, if you are not sure, please do not try to answer. Thank you!

Questions:

{79, 81, 65, 70, 72, 80, 79, 83, 59}

THIS QUESTION HAS TWO PARTS AND EACH PART HAS TWO ANSWERS,

YOU CANNOT GET FULL CREDIT UNLESS ALL PARTS ARE CORRECT AND CLEARLY LABELED!

1. Assume the data set above represents a simple random sample of test scores from Prof. Schwegel's Math 92S Chapter 7 exam. Find the mean and standard deviation for this data.

2. Assume the data set above represents the ages of all the senior citizens who attend a senior water aerobics class at the YMCA. Find the mean and standard deviation for this data.

Explanation / Answer

1. Compute mean and standard deviation as follows:

Step1. Add the numbers and divide it by 9.

79+81+65+...+59/9=668/9=74.22 (Answer)

Step2. Now subtract each number (test scores) from mean and sqaure it.

(79-74.22)2+(81-74.22)2+...(59-74.22)2=231.6484

Divide it by 9 (total number of scores)

231.6484/9=25.7387.

Now calculate the square root of the value to obtain the standard deviation.

5.07 (Answer).

2.

Step1. Add the numbers and divide it by 9.

79+81+65+...+59/9=668/9=74.22 years (Answer)

Step2. Now subtract each number (age) from mean and sqaure it.

(79-74.22)2+(81-74.22)2+...(59-74.22)2=231.6484

Divide it by 9 (total number of ages)

231.6484/9=25.7387.

Now calculate the square root of the value to obtain the standard deviation.

5.07 years (Answer).

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