7. Solve the problem. A hardware store spent $11,790 on print and TV advertising

Question

7. Solve the problem.

A hardware store spent $11,790 on print and TV advertising last year. If 4/5 of that amount was spent on print advertising, how much was spent on TV advertising?

$2358

$9432

$21,222

$11,790

8. Find the annual insurance premium.

A person's youthful-operator factor is 2.35. The annual premium for liability coverage is $198.60 for bodily injury and $165.90 for property damage.

$854.23

$880.08

$856.58

$364.50

9. Solve the problem. Round dollar amounts to the nearest cent. Use ordinary interest unless otherwise indicated.

Bob's BBQ signed a note with a face value of $19,800.00 on September 11. The note is for 90 days and carries an interest rate of 8%. Find the due date and the maturity value of the note.

December 12, $19,800.00

December 11, $20,328.00

December 10, $20,196.00

December 11, $21,384.00

$2358

$9432

$21,222

$11,790

Explanation / Answer

7) Given data:

A hardware store spent $11,790 on print and TV advertising last year.

4/5 of that amount was spent on print advertising.

Need to find the amount spent on TV advertising.

Let the amount spent on TV advertising is $X.

Amount spent on print advertising + Amount spent on TV advertising = 11,790

(4/5)(11,790) + X = 11,790

4*2,358 + X = 11,790

9,432 + X = 11,790

X = 11,790 - 9,432

X = 2358

Therefore, amount spent on TV advertising is $2358.

Related Questions

Navigate

• Browse (All)
• Browse 7
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.