The most costly US natural disaster in 2016 was a flood that hit Louisiana in Au

Question

The most costly US natural disaster in 2016 was a flood that hit Louisiana in August. This flood was caused by a persistent onshore flow of moisture-laden air from the Gulf of Mexico that was used to routinely batter the area with thunderstorms. Thirteen people lost their lives and damage estimates top $15 Billion. The image below shows the total accumulated rainfall across several southern states including the state of Louisiana for August 2016. Use the information below to estimate the total volume of water that fell in Louisiana in August 2016 measured in gallons. info: Area of Louisiana covered in 1 inch of rain = 57.271 milles^2 Area of Louisiana covered 2 inches of rain = 56, 915 milles^2 Area of Louisiana covered in 3 inches of rain = 55, 301 milles^2 Area of Louisiana covered in 4 inches of rain = 54.807 milles^2 Area of Louisiana covered in 5 inches of rain = 52, 545 miles^2 Area of Louisiana covered in 6 inches of rain = 47, 129 milles^2 Area of Louisiana covered in 7 inches of rain = 40, 532 milles^2 Area of Louisiana covered in 8 inches of rain = 37, 089 milles^2 Area of Louisiana covered in9 inches of rain = 31, 499 milles^2 Area of Louisiana covered in 10 inches of rain = 28, 635 milles^2 Area of Louisiana covered in 15 inches of rain = 17, 181 milles^2 Area of Louisiana covered in 20 inches of rain = 14, 317 milles^2 1gallon of = water = 231 in^3

Explanation / Answer

The given set of data in the tabular form is as shown below:

In order to not to count the area twice we recalculate the area covered by rain by subtracting the values of the amount of area as shown in the table below:

Now convert the area from miles2 to in2 by multiplying by 4014489600 the result is summarised below

Now we need to calculate the volume of water that is the volume of water so we just need to multiply the area coved in in2 with the depth of water in inches in order to get the volume of water in in3 and the result is summarized in the table below as:

So we have calculated the total amount of water that has been accumulated in this area is 1968585265152000 in3, in order to convert this unit in3 in gallon we need to divide it by 231 as 1 gallon= 231 in3, So it coming to be 8,522,014,134,857.14 gallon

Amount of rainfall in inch Area covered by rain in miles2 1 57271 2 56915 3 55301 4 54807 5 52545 6 47129 7 40532 8 37089 9 31499 10 28635 15 17181 20 14317

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