g = 9.80 m/s^2 = 32.2 ft/s^2 F_g = mg 1 mi = 5280 ft W = F middot Delta r = F De

Question

g = 9.80 m/s^2 = 32.2 ft/s^2 F_g = mg 1 mi = 5280 ft W = F middot Delta r = F Delta r cos theta W = integral^x_f_x F(x) dx K = 1/2 mv^2 U_g = mgy U_s = 1/2 kx^2 E_tot = K + U_g + U_s W_NC = E_tot, f - E_tot, i A 29400 N rocket is launched straight up, starting at rest. The thrust force pushing the rocket upward is 120000 N. Air resistance exerts a force of 40000 N (assumed constant). Consider the point at which the rocket is 6.0 km up. a) What is the rocket's initial mechanical energy (at launch)? b) What work does the thrust do? b) What work does air resistance do? c) What is the rocket's final mechanical energy (when it is 6.0 km up? d) What is the rocket's speed when it is 6.0 km up?

Explanation / Answer

For the first: we have

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For the first: we have

an1=(n1)nan1=(n1)n so anan1=n(n+1)n(n1)=2nanan1=n(n+1)n(n1)=2n so the sequence is defined by an=an1+2n;a1=2an=an1+2n;a1=2 Can you do the same method for the second sequence? shareciteimprove this answer

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