This is from Sullivan\'s 5th edition although I think this website has the 8th e

Question

This is from Sullivan's 5th edition although I think this website has the 8th edition (I think the questions arethe same in both versions). I was wondering why this book didn't have even answers?

So far the answers I have.

a) f(0)=0

f(6)=0

b) f(2)= -2 and f(-2)=1

c) Negative

d) Positive

e) 0,4,6

f) Not sure how to do this one.

i) x int: 0,4,6

j) y-int= 0

k) No clue

l) no clue

m) 5

n) 2

I was wondering if someone can help me with the bolded ones and perhaps check up on the other work I did. I would appreciate it so much! Thanks for the help.

Explanation / Answer

all your answers given are correct. my guess is you found these through inspection.

f) for what values of f is f(x) < 0          answer: 0 < x < 4
f(x) is the same as the vertical axis or y axis value in this problem. to be negative the graph must go below the x axis. by inspection this happens when 0 < x < 4, because all values of x between 0 and 4 are negative. 0 and 4 are not included because f(0) and f(4) are = 0 which is not negative or positive.

k) how often does the line y = -1 intersect the graph              answer: 2 times
imagine (cramster isnt letting me insert pictures) drawing a horizontal line on this graph with a y value of -1 all the way across the graph. this would intersect the negative dip between x = 0 and x = 4 twice as the function goes down below y=-1 and then comes back up through y=-1 at approximately x = 1 (1,-1) and x = 3 (3,-1)

l) how often does the line x = 1 intersect the graph                  answer : 1 time
similar to k except this time imagine drawing a vertical line through the whole graph at x = 1. it would cross the graph of your function one time around (1,-1)

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