Step 3: Enter your full question details here Given: a circle with secants AB an

Question

Step 3: Enter your full question details here Given: a circle with secants AB and CD intersecting outside the circle at E. Prove: AE x EB= CE x ED it won't let us draw a circle but it's a circle with the point ABE as a lie (e is outside the circle) and CDE. they come together at E Step 3: Enter your full question details here Given: a circle with secants AB and CD intersecting outside the circle at E. Prove: AE x EB= CE x ED it won't let us draw a circle but it's a circle with the point ABE as a lie (e is outside the circle) and CDE. they come together at E

Explanation / Answer

This problem involves two similar line segments. BE is to AE as DE is to CE. The ratio of BE to AE is the same as the ratio of DE to CE. BE/AE = DE/CE just as... BE x AE = DE x CE It might help to look up theorems regarding secants and chords...

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