Urban Community College is planning to offer courses in Finite Math, Applied Cal

Question

Urban Community College is planning to offer courses in Finite Math, Applied Calculus, and Computer Methods. Each section of Finite Math has 40 students and earns the college $40,000 in revenue. Each section of Applied Calculus has 40 students and earns the college $60,000, while each section of Computer Methods has 10 students and earns the college $25,000. Assuming the college wishes to offer a total of six sections, to accommodate 210 students, and to bring in $265,000 in revenues, how many sections of each course should it offer?

Explanation / Answer

first let a= Finite Math = 40 students and 40 K dollars b= Applied Calculus = 40 students and 60 K dollars c= Computer Methods= 10 students and 25 K dollars total sections = 6 total money = 265 K total students = 210 so 6 = a + b+ c 210 = 40a + 40b + 10c 265 = 40a + 60b + 25c now plug and chug so take the formulas and solve for aq,b,c I will get you started solve for a a= 6 - b -c put that into the others 210 = 40(6 - b -c) + 40b + 10c 265 = 40(6 - b -c) + 60b + 25c expand 210 - 240 = - 30c 265 - 240 = 20b - 15c already we can see that c = 1 so there is 1 Computer Methods class -30 = -30c now solve for b and a

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