Point charges +4.3 µC and -2.2 µC are placed on the x -axis at (10 m, 0) and (-1

Question

Point charges +4.3 µC and -2.2 µC are placed on the x-axis at (10 m, 0) and (-10 m, 0), respectively. (a) Find the point to the left of the negative charge where the electric potential vanishes.
x = ______________m

Point charges +4.3 µC and -2.2 µC are placed on the x-axis at (10 m, 0) and (-10 m, 0), respectively. (a) Find the point to the left of the negative charge where the electric potential vanishes.
x = ______________m

(a) Find the point to the left of the negative charge where the electric potential vanishes.
x = ______________m

Explanation / Answer

q1 = 4.3 µC, q2 = -2.2 µC, a = 10 m, Assume the distance between the point and q2 is b then the distance between the point and q2 is 20 + b net potential of the point = k[q1/(20 + b) + q2/b] = 0 q1/(20 + b) = -q2/b (20 + b)/b = -q1/q2 = 4.3/2.2 20/b + 1 = 4.3/2.2 20/b = 4.3/2.2 - 1 = 0.9545 b = 20.95 m answer: x = -20.95 m

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