Poi A coil with five turns of wire rests on an inclined plane that is titled at

Question

Poi A coil with five turns of wire rests on an inclined plane that is titled at 20.0° above the horizontal. The turns are circular with radius 0 168 m and the total resistance of the coil is 0220 ? There is uniform magnetic field whose magnitude decreases uniformly from 0.890 T to 0.00 T in 1.170 seconds. The field is horizontal, pointing in the direction shown in the figure ere a Des What is the induced voltage in the coil? Give your answer as positive) Pol Yo Yo giv Number 0.79 volts What is the magnitude of the induced current in the coil? Yo ar at 3.61 amps When seen from above, in what direction is the induced current flowing? O O Clockwise Counter-clockwise There is no induced current

Explanation / Answer

emf induced=rate of change of flux

flux=dot product of magnetic field and area vector

area vector of the loop is perpendicular to the loop i.e.making an angle 70 degree above horizontal.

angle with magnetic field=180-70=110 degrees

then flux==B*pi*r^2*cos(110)

emf induced =number of turns*time derivative of flux

=5*change in B*pi*r^2*cos(110)

=5*((0-0.89)/1.17)*pi*0.168^2*cos(110)

=0.115 volts

part b::

magnitude of induced current=induced emf/resistance

=0.115/0.22

=0.522 A

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