I am stuck on how to do this question. In Albuquerque N.M, themaximum allowable

Question

I am stuck on how to do this question. In Albuquerque N.M, themaximum allowable sound level from a car's exhaust is 96dB. What isthe intensity of such a sound? L=10*log I/Io1 Where I is theintensity of sound, in watts per square meter(w/m^2) &Io=10^-12w/m^2. So far I have L=10*logI/Io =10*log I am stuck on how to do this question. In Albuquerque N.M, themaximum allowable sound level from a car's exhaust is 96dB. What isthe intensity of such a sound? L=10*log I/Io1 Where I is theintensity of sound, in watts per square meter(w/m^2) &Io=10^-12w/m^2. So far I have L=10*logI/Io =10*log

Explanation / Answer

To do this, set up the equation: 96 = 10 log (x/(10^-12)).  Next, divide both sides by 10 to get: 9.6 = log (x/(10^-12)).  Use the inverse logarithm, 10^x, on both sides: 10^9.6 = 10^(log (x/(10^-12)).  The inverse logarithm gets rid of the log so that you have: 3981071706 = x/(10^-12).  Then solve for x and you get that the intensity is .00398 W/m^2.

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