Second die First die 1 2 3 4 5 6 1 (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) 2 (2,1) (

Question

                                   Second die

First die

1

2

3

4

5

6

1

(1,1)

(1,2)

(1,3)

(1,4)

(1,5)

(1,6)

2

(2,1)

(2,2)

(2,3)

(2,4)

(2,5)

(2,6)

3

(3,1)

(3,2)

(3,3)

(3,4)

(3,5)

(3,6)

4

(4,1)

(4,2)

(4,3)

(4,4)

(4,5)

(4,6)

5

(5,1)

(5,2)

(5,3)

(5,4)

(5,5)

(5,6)

6

(6,1)

(6,2)

(6,3)

(6,4)

(6,5)

(6,6)

                                   Second die

First die

1

2

3

4

5

6

1

(1,1)

(1,2)

(1,3)

(1,4)

(1,5)

(1,6)

2

(2,1)

(2,2)

(2,3)

(2,4)

(2,5)

(2,6)

3

(3,1)

(3,2)

(3,3)

(3,4)

(3,5)

(3,6)

4

(4,1)

(4,2)

(4,3)

(4,4)

(4,5)

(4,6)

5

(5,1)

(5,2)

(5,3)

(5,4)

(5,5)

(5,6)

6

(6,1)

(6,2)

(6,3)

(6,4)

(6,5)

(6,6)

Explanation / Answer

Number of pairs aboce summing to 7 is 6. Hence P(7) =6/36.   Number of pairs adding to 11 is 2.  thus P(7 or 11) = 6/36 + 2/36 =8/36. So the probability ofNOT getting a 7 or 11 is 1 - P(7 or 11) = 1- 8/36 = 28/36= 7/9.

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