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Hello everyone, this is probably simple, butI don\'t understand and could use an

ID: 3091509 • Letter: H

Question

Hello everyone, this is probably simple, butI don't understand and could use any help. Thank you.

Question: In whichquadrant(s) could a point be located if its coordinates arereciprocals of each other?

I did not understand so I sentthis to my teacher:

I believe the answer is: the same quadrant as the originatingcoordinates. for example: If (3,5) or 3(x),5(y) = 3/5 then wouldthe reciprocal plot be (5,3)?

or would the reciprocal for (3,5) be (1/3,1/5)? If the answer isthe secondary then wouldn't graphing this get you 2 points graphedfor the ordered pair ( one for 1/3 and one for 1/5) instead of 1,since I believe when graphing fractions x is the numerator and y isthe denominator (or would there be a way to simplify)?

The response to my question from my teacher was:

where would the coordinates be (x,1/x) or (1/y,y)?

That could happen in two places. (3,1/3) and (-3,-1/3) areexamples.



I am completely clueless if he answered my question and or what heis asking me. Thank you for your help ahead of time.

Explanation / Answer


So, for example, if x=2, then (2,1/2) is a possible coordinatepair.
It seems to me that your intuition for this problem iscorrect, in that the coordinates would have to be in a quadrantwhere their signs are the same.
When you take the reciprocal of 2, you don't change it's sign. Therefore, the example of (2,1/2) must be in QuadrantI.
This is NOT the only quadrant that the coordinates could bein. They could also be in Quadrant III, because if you havex=-2, then you have (-2,-1/2).
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