UseDescartes\'s Rule of Signs to determine the possible numbers ofpositive and n

Question

UseDescartes's Rule of Signs to determine the possible numbers ofpositive and negative real zeros of the function. g(x) = 3x3 4x2 15 The number of variations in sign in g(x) is1---Select---012345. Therefore, the number of 2---Select---positivenegative real zeros of g is 3---Select---012345either 3 or 1either 3 or 2either 3 or 0either 4 or 3either 4 or 2either 4 or 1either 4 or 0either 5 or 4either 5 or 3 or 1either 5 or 2 or 0.

The number of variations in sign in g(-x) is4---Select---012345. Therefore, the number of 5---Select---positivenegative real zeros of g is 6---Select---012345either 3 or 1either 3 or 2either 3 or 0either 4 or 3either 4 or 2either 4 or 1either 4 or 0either 5 or 4either 5 or 3 or 1either 5 or 2 or 0. UseDescartes's Rule of Signs to determine the possible numbers ofpositive and negative real zeros of the function. g(x) = 3x3 4x2 15 The number of variations in sign in g(x) is1---Select---012345. Therefore, the number of 2---Select---positivenegative real zeros of g is 3---Select---012345either 3 or 1either 3 or 2either 3 or 0either 4 or 3either 4 or 2either 4 or 1either 4 or 0either 5 or 4either 5 or 3 or 1either 5 or 2 or 0.

The number of variations in sign in g(-x) is4---Select---012345. Therefore, the number of 5---Select---positivenegative real zeros of g is 6---Select---012345either 3 or 1either 3 or 2either 3 or 0either 4 or 3either 4 or 2either 4 or 1either 4 or 0either 5 or 4either 5 or 3 or 1either 5 or 2 or 0. g(x) = 3x3 4x2 15

Explanation / Answer

One sign change when x is positive(between the first term andsecond term). The number of variations in sign in g(x) is1. Therefore, the number of positive real zerosof g is 1. Zero sign changes when x is negative. The number of variations in sign in g(-x) is0. Therefore, the number of  negative realzeros of g is 0. Zero sign changes when x is negative. The number of variations in sign in g(-x) is0. Therefore, the number of  negative realzeros of g is 0.

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