Graph the quadratic function. Plot the vertex and anyintercepts. f ( x ) = ( x 2
ID: 3089272 • Letter: G
Question
Graph the quadratic function. Plot the vertex and anyintercepts.
f(x) = (x 2)2 +6
STEP1:
Identify the vertex of theparabola.
(x, y) = ( 1, 2)
STEP2:
Identify the y-interceptof the parabola.
(x, y) = ( 3, 4)
STEP3:
How many x-intercepts are there?
5
0
1
2
STEP4:
Identify the axis of symmetry.
x =
6
STEP1:
Identify the vertex of theparabola.
(x, y) = ( 1, 2)
STEP2:
Identify the y-interceptof the parabola.
(x, y) = ( 3, 4)
STEP3:
How many x-intercepts are there?
5
0
1
2
STEP4:
Identify the axis of symmetry.
x =
6
Explanation / Answer
The vertex form of the quadratic is y = (x - h)2 + k, where the point ( h , k ) is thelocation of the vertex. In this case, the vertex is at ( 2, 6 ). The y-intercept occurs when x = 0. Thus, they-intercept is ( 0 - 2)2 +6 = 4. y-intercept =4. There are NO x-intercepts. Graph the given eqn and youwill not see any x-intercepts at all. The axis of symmetry occurs at x = - b /2a. To see the values of a and b, we have to put thegiven quadratic in standard form like y =ax2 + bx + c. Our eqn is y = x2 - 4x +10, so a= 1, and b = -4. x =- b / 2a = +4 / 2 = 2. Axis of symmetry isx = 2.Related Questions
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