how do you find the x and y intercepts of these equations,WITHOUT a graphing cal
ID: 3088792 • Letter: H
Question
how do you find the x and y intercepts of these equations,WITHOUT a graphing calculator because it is not allowed for thetest. Please give detailed explanations. The text book book says to factor the ploynomial to find thex-intercept and for the y-intercept, set it to zero---I'mconfused. y = (x-2)3 + 8 answer: says x,y intercept = 0 y = x3 -9x answer: say y intercept is -3, 0, 3 and x intercept is 0 how do you find the x and y intercepts of these equations,WITHOUT a graphing calculator because it is not allowed for thetest. Please give detailed explanations. The text book book says to factor the ploynomial to find thex-intercept and for the y-intercept, set it to zero---I'mconfused. y = (x-2)3 + 8 answer: says x,y intercept = 0 y = x3 -9x answer: say y intercept is -3, 0, 3 and x intercept is 0Explanation / Answer
anx-intercept is a point on the graph whereyis zero, ie the x-axis an y-intercept is a point on the graph wherexis zero, ie the y-axis so to find x-intercept, you plug in y = 0 to the polynomial for example y = (x-2)3 + 8 0 = (x-2)3 + 8 to solve for x -8 = (x - 2)3 -2 = x - 2 x = 0 x-intercept is at (0,0) to fin y-intercept, you plug in x=0 to the polynomial and solve fory, from above we know when x = 0, y = 0 as for y = x3 -9x find x-intercept, we set y = 0 = x (x2 - 9) = x(x-3)(x+3) x = 0, 3 or -3 so the x-intercepts are at (0,0) (3,0) (-3,0) to find y-intercept, we set x = 0 and solve for y, in thiscase y will be 0 so the y-interceptis at (0,0)
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