how do i solve this problem? and why is that the correct answer? Question 10 0/3

Question

how do i solve this problem? and why is that the correct answer?

Question 10 0/3 pts A 1.00 kg block is on a frictionless, 200 inclined plane. The block is attached to a spring (k 25 N/m) that is fixed to a wall at the bottom of the incline. A light string attached to the block runs over a frictionless pulley to a 40.0 g suspended mass. The suspended mass is given an initial downward speed of 1.50 m/s. How far does it drop before coming to rest? (Assume the spring is unlimited in how far it can stretch.) 0.48 m 0.50m 0.57 m 0.21 m · 0.12 m 0.34 m

Explanation / Answer

0.04 (a) = 0,04 (g) - T

0.04 (a) = 0.392 - ( Mgsin theta + Kx)

0.04 ( 1.50^2/ 2x ) = 0.392 - (9.8 sin 20 + 25 x)

0.045 / x = 0.392 - (3.352 + 25x)

0.045 / x= -2.96 - 25x

25x^2 + 2.96 x + 0.045 =0

solving for x,

x= 0.012 m apprx

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.