is Guestion: 1 pt 13 of 21 (10 complete) This Test: 21 pts pos According to a su
ID: 3075242 • Letter: I
Question
is Guestion: 1 pt 13 of 21 (10 complete) This Test: 21 pts pos According to a survey, 59% of the residents of a city oppose a downtown casino. Of through (c). these 59% about 8 out of 10 strongly oppose the casino. Complete parts (a) (a) Find the probability that a randomly selected resident opposes the casino and strongly apposes the casino. (b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino (c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino? Explain (a) The probability that a randomly selected resident opposes the casino and strongly opposes the casino is Round to three decimal places as needed.) b) The probability that a randomly selected resident who opposes the casino does not strongly opposes the casino is (Round to three decimal places as needed.) (c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino? Explain. Choose the correct answer below O A. No, this is not unusual because the probability is less than or equal to 0.05. O B. No, this is not unusual because the probability is not less than or equal to 0.05 O C. Yes, this is unusual because the probability is not less than or equal to 0.05 O D. Yes, this is unusual because the probability is less than or equal to 0 05. Click to select your answerls).Explanation / Answer
Solution:- Given that P(A) = 0.59, P(B|A) = 0.8
(a) P(A and B) = P(B|A)*P(A) = 0.59 * 0.8 = 0.472
(b) P(B' | A) = 1 - P(B|A) = 1 - 0.8 = 0.2
Second method :
P(B' | A) = P(B'A)/P(A) = (P(A) - P(A and B))/ P(A) =
= (0.59 - 0.472)/0.59
= 0.2
c) option B.
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