14 Pew study found that the average US Facebook user has 338 friends. The study
ID: 3072730 • Letter: 1
Question
14 Pew study found that the average US Facebook user has 338 friends. The study also found that the med an US Facebook user has 200 friends. What does this mply about the distribution of the variable "number of Facebook friends"? You have two attempts for this problem, and five attempts each for the remaining problems) O The distribution is bimodal O The distribution is normal The distribution is trending O The distribution is symmetrical O The distribution is right skewed O The distribution is approximately Q3 O The distribution is left skewed pew study did not report a standard deviation, but given the number of racebook friends is highly variable, let's suppose that the standard deviation is i98. Let's lso suppose that 338 and 198 are population values (they aren't, but we don't know the true population values so this is the best we can do). (Use 3 decimal recision for parts a, b., and c) . If we randomly sample 120 Facebook users, what is the probability that the mean number of friends will be less than 3467 . If we randomly sample 118 Facebook users, what is the probability that the mean number of friends will be less than 3177 If we randomly sample 600 Facebook users, what is the probability that the mean number of friends will be greater than 3467 Round to the nearest integer for parts d. and e.) If we repeatedly take samples of n-60 ll lie between 0 Facebook users and construct a sampling distribution of mean number or friends, we should expect that 95% of sample means and The 75th percentile of the sampling distribution of mean number of friends, from samples of size n 120, isExplanation / Answer
Solution
Given that median = 200
and mean = 338
so mean> median
a. The distribution is right skewed
b. Given that mean = 338 and s = 198
i. n = 120
P(X<346) = P(Z<(346-338)/198/1200.5)
P(Z<0.44) = 0.67
ii. P(X<317) = P(Z<(317-338)/198/1180.5)
P(Z<-1.15) = 0.125
iii. P(X>346) = P(Z>(346-338)/198/6000.5)
P(z>0.99) = 0.161
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