Find the range, variance, and standard deviation for the given sample data, if p

Question

Find the range, variance, and standard deviation for the given sample data, if possible. If the measures of variation can be obtained for these values, do the results make sense? Biologists conducted experiments to determine whether a deficiency of carbon dioxide in the soil affects the phenotypes of peas. Listed below are the phenotype codes, where 1equalssmooth-yellow, 2equalssmooth-green, 3equalswrinkled yellow, and 4equalswrinkled-green. 11413133222312222222 Can the range of the sample data be obtained for these values? Choose the correct answer below and, if necessary, fill in the answer box within your choice. A. The range of the sample data is nothing. (Type an integer or a decimal. Do not round.) B. The range of the sample data cannot be calculated. Can the standard deviation of the sample data be obtained for these values? Choose the correct answer below and, if necessary, fill in the answer box within your choice. A. The standard deviation of the sample data is nothing. (Round to one decimal place as needed.) B. The standard deviation of the sample data cannot be calculated. Can the variance of the sample data be obtained for these values? Choose the correct answer below and, if necessary, fill in the answer box within your choice. A. The variance of the sample data is nothing. (Round to one decimal place as needed.) B. The variance of the sample data cannot be calculated. Do the results make sense? A. The measures of variation do not make sense because the standard deviation cannot be greater than the variance. B. While the measures of variation can be found, they do not make sense because the data are nominal; they don't measure or count anything. C. The measures of variation make sense because the data is numeric, so the spread between the values is meaningful. D. It makes sense that the measures of variation cannot be calculated because there is not a large enough sample size to calculate the measures of variation.

Explanation / Answer

(a) RANGE

Lowest value: 1
Highest value: 4

Range: 3

(b) Standard Deviation

Find the mean=2.05

3.8025

The standard deviation of the data set is: =0.8256

(c) Variance

The variance of the data set is: var=0.6816 (square of standard devition)

since the data is nominal, above calculations does not make any sense. In case of nominal data, only the mode makes sense.

data data-mean (data - mean)2 1 -1.05 1.1025 1 -1.05 1.1025 1 -1.05 1.1025 1 -1.05 1.1025 1 -1.05 1.1025 2 -0.05 0.0025 2 -0.05 0.0025 2 -0.05 0.0025 2 -0.05 0.0025 2 -0.05 0.0025 2 -0.05 0.0025 2 -0.05 0.0025 2 -0.05 0.0025 2 -0.05 0.0025 2 -0.05 0.0025 3 0.95 0.9025 3 0.95 0.9025 3 0.95 0.9025 3 0.95 0.9025 4 1.95

3.8025

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.