x WileyPLUS https://edugen.wileyplus.com/edugen/lti/main.uni Montgomery, Applied

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x WileyPLUS https://edugen.wileyplus.com/edugen/lti/main.uni Montgomery, Applied Statistics and Probability for Engineers, 7e Hele I System Announcements PRINTER VERSION BACK NEXT Reserve Problems Chapter 3 Section 3 Problem 7 Incorrect Consider the following circuit. The probability that each device functions correctly is pi 0.87 and p20.73. Assume that devices fail independently. P2 Let the random variable X denote the number of failed devices. Calculate the mean for X. 0.3649 exact number, no tolerance Click if you would like to Show Work for this question: Open Show Work LINK TO TEXT SAVE FOR LATER T ANSWER Question Attempts: Unlimited MapleNet 10:31 PM 9/12/2018

Explanation / Answer

Mean number of failed devices = sum of (number of devices failed x probability of corresponding failure)

= 0 x P(0 devices fail) + 1 x P(1 device fail) + 2 x P(2 devices fail)

= 0 + 1 (0.87x0.27 + 0.13x0.73) + 2x(0.13x0.27)

= 0.3298 + 0.0702

= 0.4000

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