x KG Two equally charged pa x C Two Equally charged Pe x C Secure https://edugen

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x KG Two equally charged pa x C Two Equally charged Pe x C Secure https://edugen wileyplus com edugen/student/mainfr uni Chapter 21 4.59 103 m/s directly toward a very distant proton that is at rest. An electron is projected with an initial speed hat the proben remains at rest, By calculating the s large relative to the electron Because the proton mass force, determine the distance between the two particles hen t work done on the electron by the electrostati instantaneously has speed 2vi. Click you would like to show work for this Question Attempts o of 1 used SAVE LATER

Explanation / Answer

Applying energy conservation,

PEi + KEi = PEf + KEf

{ electric potential energy is zero when they are far apart }

0 + m (v^2) /2 = k q1 q2 / r + m (2v)^2 / 2

(9.109 x 10^-31) (4.59 x 10^5)^2 / 2 = - (9 x 10^9 x (1.6 x 10^-19)^2 / R) + [ (9.109 x 10^-31) (2 x 4.59 x 10^5)^2 / 2]

2.304 x 10^-28 / r = 2.879 x 10^-19

r = 8 x 10^-10 m

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