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jtuuelluPl ayerHomework.aspx?homeworkld-4963090708tquestionld-108flushed-false&c

ID: 3069800 • Letter: J

Question

jtuuelluPl ayerHomework.aspx?homeworkld-4963090708tquestionld-108flushed-false&cld-51522828centerwin. Fall 2018 STA2023 TR 9:30-10:45 Ccambrannson Exantus & 9/12/18 10:19 PM Homework: 3.3 Score: 0 of 1 pt 3.3.5 Save 10 of 15 (8 complete) HW Score: 49.33%, 7.4 of 15 pt Question Help * Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 71.9 Mbps. The complete list of 50 data speeds has a mean of x- 16.47 Mbps and a standard deviation of s 19.31 Mbps. b. How many standard deviations is that [the difference found in part (a)j? d. If we consider data speeds that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the carrier's highest n a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? te c. Convert the carrier's highest data speed to a z score te data speed significant? a. The difference is Mbpg Type an integer or a decimal. Do not round.) Enter your answer in the answer box and then click Check Answ er 3 :

Explanation / Answer

Solution:

a.What is the difference between carrier's highest data speed and the mean of all 50 data speeds?
= (71.9 - 16.47) = 55.43

b. How many standard deviations is that [the difference found in part (a)]?
sd = 55.43/19.31
= 2.87053

c. Convert the carrier's highest data speed to a z score.
z = (X - mu)/sd
= (71.9- 16.47 )/19.31
= 2.87053

d. Yes the carrier's highest data speed is significant because it is greater than 2.