The table shows the results for 13 students on a 16 question multiple-choice exa

Question

The table shows the results for 13 students on a 16 question multiple-choice exam. A “1” means the student got the question correct, and a “0” means the student did not get the question correct. Copy the table into an Excel spreadsheet and make sure to save it to your computer.

Take a teacher's point of view to analyze the test to see if any question(s) should be thrown out, changed, or altered in any way.
• Your response needs to be at least 300 words.
• Base your answer on these assumptions
o Questions #1-4 are adding fractions.
o Questions #5-8 are subtracting fractions.
o Questions #9-12 are multiplying fractions.
o Questions #13-16 are dividing fractions.
o Students are not able to use calculators on the test.
• Based on the data give at least three reasons why question(s) should or should not be thrown out, changed, or altered.
• Explain and show any work needed for this calculation.  
• Describe the assumptions in making your judgments.
• Providecompelling rationale for why each assumption is appropriate or inappropriate.
• Explain whether and how your findings are valid.
• Explain whether and how your findings are reasonable.
• Provide deep and thoughtful judgments, drawing insightful, carefully qualified conclusions from the test data.

Student #1 #2 #3 #5 #6 #7 #8 #9 #10 #11 #12 #13 #14 #15 #16 Frequency Percentage Andy 1 0 1 0 1 1 1 1 1 1 1 0 1 1 1 13 76.47% Creed 0 0 0 0 1 1 0 1 0 1 0 1 0 1 0 6 35.29% Darryl 0 1 1 1 0 0 1 0 1 1 0 1 0 1 1 10 58.82% Dwight 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 14 82.35% Gabe 1 1 1 0 0 1 1 0 1 1 1 1 1 1 1 13 76.47% Holly 0 1 0 0 1 1 1 1 1 1 1 1 0 1 1 12 70.59% Jim 1 1 1 1 1 1 1 0 1 1 1 1 0 1 1 14 82.35% Kevin 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 16 94.12% Michael 1 1 0 0 0 1 0 0 0 1 0 0 0 0 0 5 29.41% Pam 1 1 0 1 1 1 1 1 0 1 0 1 0 1 0 11 64.71% Phyllis 1 0 1 0 0 1 1 1 0 1 0 1 0 1 0 9 52.94% Stanley 1 1 0 1 0 0 1 1 0 1 1 0 0 1 1 10 58.82% Toby 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 15 88.24%

Explanation / Answer

a)

mean = 100*(1/5) = 20

standard deviation = sqrt[N*p(1-p)] = sqrt(100*1/5*4/5) = 4

b)

z = (x-)/ = (60-20)/4 = 10

that's 10 standard deviation away from mean, the probabilty of that happending is very low. so it would be unusual for a student to pass the exam by guessing and getting at least 60 correct answers

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