A university professor drives from his home in Cary to his university office in

Question

A university professor drives from his home in Cary to his university office in Raleigh each day. His car, which is rather old, fails to start one out of eight times and he ends up taking his daughter’s car. Furthermore, the rate of growth of Cary is so high that traffic problems are common. The professor finds that 70% of the time, traffic is so bad that he is forced to drive past his preferred exit off the beltline, Western Boulevard, and take the next exit, Hillsborough Street. What is the probability of seeing this professor driving to his office along Hillsborough Street, in his daughter’s car?

Explanation / Answer

Ans:

P(fails to start)=1/8

P(traffic jam)=0.7

Both events(car fails to start and traffic jam )are independent.

So,

P(daughter's car and Hillsborough street)=P(daughter's car)*P(Hillsborough street)

=P(fails to start)*P(traffic jam)

=(1/8)*0.7

=0.0875

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