The weight of people in a small town in Missouri is known to be normally distrib
ID: 3066904 • Letter: T
Question
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 197 pounds and a standard deviation of 31 pounds. On a raft that takes people across the river, a sign states, “Maximum capacity 3,400 pounds or 17 persons.” What is the probability that a random sample of 17 persons will exceed the weight limit of 3,400 pounds? Use Table 1. (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)
probablity:
Data from the Bureau of Labor Statistics’ Consumer Expenditure Survey (CE) show that annual expenditures for cellular phone services per consumer unit increased from $263 in 2001 to $583 in 2007. Let the standard deviation of annual cellular expenditure be $51 in 2001 and $206 in 2007. Use Table 1.
What is the probability that the average annual expenditure of 100 cellular customers in 2001 exceeded $248? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)
What is the probability that the average annual expenditure of 100 cellular customers in 2007 exceeded $578? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)
a.What is the probability that the average annual expenditure of 100 cellular customers in 2001 exceeded $248? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)
Explanation / Answer
1)
exceeding capcaity 3400 means average weight should increase 3400/17 =200 pound
probability that a random sample of 17 persons will exceed the weight limit of 3,400 pounds:
2)
a)
b)probability that the average annual expenditure of 100 cellular customers in 2007 exceeded $578:
for normal distribution z score =(X-?)/? here mean= ?= 197 std deviation =?= 31.0000 sample size =n= 17 std error=?x?=?/?n= 7.5186Related Questions
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