12 For the above data- coin in one\'s pocket-Sam wants to determine whether men

Question

12 For the above data- coin in one's pocket-Sam wants to determine whether men carry more change than women, at the 0.10-level of significance. Pocket Change (cents)t Women: 23 24 31 28 21 Men: 32 20 22 25 34 13, He then realizes that a 95% confidence interval would be appropriate, so construct one. 1. Fie tle For the above data-men's termine whether men's forearms are the same circumference, at the 0.01- level of significance. Men's Forearms (incs) right and r den mala arm Right: 12.25 11.25 10.75 12.75 11.75 Left: 13.75 10.75 11.00 12.50 .12.50 t G nger wants to de- 15. She then realizes that a 95% confidence interval would be appropriate, so construct one

Explanation / Answer

12)
Hypothesis;
H0 : mu1 = mu2
Ha : mu1 > mu2

Test statistics:

x1 = 26.6 ,x2 =25.4, s1 = 6.1482 , s2 = 4.0373 , n1 = n2 = 5

t = (x1 - x2) / sqrt(s1^2/n1 +s2^2/n2)
= ( 26.6 - 25.4)/sqrt(6.1482^2/5 + 4.0373^2/5)
= 0.3648

P value is calculated using t = 0.3648 with df = 8 at 0.05 significance level

P value = .3624

we fail to reject the null hypothesis.

13)

t value at 95% = 2.306
CI = (x1 - x2) +/- t * sqrt(s1^2/n1 +s2^2/n2)
= ( 26.6 - 25.4) +/- 2.306 * sqrt(6.1482^2/5 + 4.0373^2/5)
= ( -6.3853,8.7853)

14)

Hypothesis;
H0 : mu1 = mu2
Ha : mu1 not equal to mu2

Test statistics:

x1 = 11.75 ,x2 =12.1, s1 = 0.7906 , s2 = 1.2324 , n1 = n2 = 5

t = (x1 - x2) / sqrt(s1^2/n1 +s2^2/n2)
= ( 11.75 - 12.1)/sqrt(0.7906^2/5 + 1.2324^2/5)
= -0.5345

P value is calculated using t = -0.5345 with df = 8 at 0.05 significance level

P value = .6072

we fail to reject the null hypothesis.

13)

t value at 95% = 2.306
CI = (x1 - x2) +/- t * sqrt(s1^2/n1 +s2^2/n2)
= (11.75 - 12.1) +/- 2.306 * sqrt(0.7906^2/5 + 1.2324^2/5)
= (-1.8600 ,1.1600)

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