Given a standardized normal distribution (with a mean of 0 and a standard deviat

Question

Given a standardized normal distribution (with a mean of 0 and a standard deviation of 1), complete parts (a) through (d). EEB Click here to view page 1 of the cumulative standardized normal distribution table. EEB Click here to view page 2 of the cumulative standardized normal distribution table. a. What is the probability that Z is less than 1.02? The probability that Z is less than 1.02 is Round to four decimal places as needed.) b. What is the probability that Z is greater than -0.23? The probability that Z is greater than -0.23 is Round to four decimal places as needed.) c. What is the probability that Z is less than -0.23 or greater than the mean? The probability that Z is less than -0.23 or greater than the mean is Round to four decimal places as needed.) d. What is the probability that Z is less than 0.23 or greater than 1.02? The probability that Z is less than -0.23 or greater than 1.02 is (Round to four decimal places as needed.)

Explanation / Answer

We will be using a standard normal distribution table for this solution

(a) P(Z<1.02) = 0.8461(value from the table directly).

(b) P(Z>-0.23) = P(Z<0.23) = 0.5910

(c) P(Z<-0.23 or Z>0) = P(Z<-0.23)+P(Z>0) = 0.409+0.5 = 0.909

(d) P(Z<-0.23 or Z>1.02) = P(Z<-0.23)+P(Z>1.02) = 0.409+0.1539 = 0.5629

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