Given a standardized normal distribution (with a mean of 0 and a standard deviat

Question

Given a standardized normal distribution (with a mean of 0 and a standard deviation of 1), complete parts (a) through (d). EEB Click here to view page 1 of the cumulative standardized normal distribution table. EEB Click here to view page 2 of the cumulative standardized normal distribution table. a. What is the probability that Z is less than 1.08? The probability that Z is less than 1.08 is Round to four decimal places as needed.) b. What is the probability that Z is greater than 0.23? The probability that Z is greater than - 0.23 is Round to four decimal places as needed.) c. What is the probability that Z is less than -0.23 or greater than the mean? The probability that Z is less than -0.23 or greater than the mean is Round to four decimal places as needed.) d. What is the probability that Z is less than 0.23 or greater than 1.08? The probability that Z is less than - 0.23 or greater than 1.08 is Round to four decimal places as needed.)

Explanation / Answer

Solution:

Given
mean = 0 and a standard deviation = 1
a) The probability that Z is less than 1.08 is
P(Z < 1.08) = 0.8599

b) The probability that Z is greater than -0.23 is
P(Z < -0.23) = 1P(Z < 0.23)
= 10.591 = 0.409

c) The probability that Z is less than -0.23 or greater than the mean is
P(-0.23< Z < 0) = P(Z < 0) P(Z<0.23 )
= 0.5 - 0.409
= 0.091
d) The probability that Z is less than -0.23 or greater than 1.08 is
P(-0.23< Z < 1.08) = P ( Z<1.08 )P (Z<0.23 )
= 0.8599 - 0.409
= 0.4509

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.