x 0 1 2 3 4 5 0. 0.0845 P(x) 0.2700 0.3452 0.2207 0.0706 0.0090 x 0 1 2 3 4 5 0.
ID: 3065974 • Letter: X
Question
x
0
1
2
3
4
5
0.
0.0845
P(x)
0.2700
0.3452
0.2207
0.0706
0.0090
x
0
1
2
3
4
5
0.
0.0845
P(x)
0.2700
0.3452
0.2207
0.0706
0.0090
Based on data from a car bumper sticker study, when a car is randomly selected, the number of bumper stickers and the corresponding probabilities are as shown below Complete parts (a) through (d). Table of numbers of bumper stickers and probabilitie EEB Click the icon to view the data table a. Does the given information describe a probability distribution? P(x) 0.780 0.094 0.049 0.024 0.014 0.014 0.008 0.007 0.006 0.004 0 Yes b. Assuming that a probability distribution is described, find its mean and standard deviation 4 The mean is. (Round to the nearest tenth as needed.) Enter your answer in the answer box and then click Check Answer Print Done partsExplanation / Answer
1)
mean = summation of (x *P(x))
= 0 * 0.78 + 1 * 0.094 + 2 * 0.049 + 3 * 0.024 + 4 * 0.014 + 5 * 0.014 + 6 *0.008 + 7 * 0.007 + 8 * 0.006 + 9 * 0.004
=0.571
std.deviation = (0-0.571)^2 * 0.78 + (1 -0.571)^2 * 0.094 + (2-0.571)^2 * 0.049 + (3-0.571)^2 * 0.024 + (4-0.571)^2 * 0.014 + (5-0.571)^2 * 0.014 + (6-0.571)^2 *0.008 + (7-0.571)^2 * 0.007 + (8-0.571)^2 * 0.006 + (9-0.571)^2 * 0.004
= 2.093
2)
mean = 0 * 0.329 + 1 * 0.443 + 2 * 0.199 + 4 * 0.029
= 0.928
The table is a probability distribution
3)
mean = 0 * 0.0845 +1 * 0.27 + 2 * 0.3452 + 3 * 0.2207 + 4 * 0.0706 + 5 * 0.009
= 1.9499
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